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In this example, the molar mass of CO 2 is about 44 g/mol (Carbon's molar mass is ~12 g/mol and oxygen's is ~16 g/mol, so the total is 12 16 16 = 44) Multiply 04 moles CO 2 x 44 g/mol CO 2 = ~367 grams The theoretical yield of the experiment is 367 grams of CO 2The theoretical molar yield is mol (the molar amount of the limiting compound, acetic acid) The molar yield of the product is calculated from its weight (132 g ÷ g/mol = 15 mol) The % yield is calculated from the actual molar yield and the theoretical molar yield (15 mol ÷ mol × 100% = 75%)Mass(NH3) = moles(NH3) × molar mass(NH3) predicted mass NH3= 8 × (14 3 × 1) = 8 × 17 = 136 g Theoretical yield= predicted mass = 136 g Percentage yield = (actual yield÷ theoretical yield) × 100 Substituting the vales for actual yield and theoretical yield into the equation 4 4 Reaction Yields Chemistry How to calculate the maximum yield